Optimal. Leaf size=296 \[ \frac{20 x+37}{217 (2 x+1)^{3/2} \left (5 x^2+3 x+2\right )}-\frac{4680}{10633 \sqrt{2 x+1}}-\frac{820}{4557 (2 x+1)^{3/2}}-\frac{5 \sqrt{\frac{1}{434} \left (2632525 \sqrt{35}-12504542\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{10633}+\frac{5 \sqrt{\frac{1}{434} \left (2632525 \sqrt{35}-12504542\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{10633}+\frac{5 \sqrt{\frac{2}{217} \left (12504542+2632525 \sqrt{35}\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{10633}-\frac{5 \sqrt{\frac{2}{217} \left (12504542+2632525 \sqrt{35}\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{10633} \]
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Rubi [A] time = 0.44318, antiderivative size = 296, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {740, 828, 826, 1169, 634, 618, 204, 628} \[ \frac{20 x+37}{217 (2 x+1)^{3/2} \left (5 x^2+3 x+2\right )}-\frac{4680}{10633 \sqrt{2 x+1}}-\frac{820}{4557 (2 x+1)^{3/2}}-\frac{5 \sqrt{\frac{1}{434} \left (2632525 \sqrt{35}-12504542\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{10633}+\frac{5 \sqrt{\frac{1}{434} \left (2632525 \sqrt{35}-12504542\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )}{10633}+\frac{5 \sqrt{\frac{2}{217} \left (12504542+2632525 \sqrt{35}\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{10633}-\frac{5 \sqrt{\frac{2}{217} \left (12504542+2632525 \sqrt{35}\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )}{10633} \]
Antiderivative was successfully verified.
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Rule 740
Rule 828
Rule 826
Rule 1169
Rule 634
Rule 618
Rule 204
Rule 628
Rubi steps
\begin{align*} \int \frac{1}{(1+2 x)^{5/2} \left (2+3 x+5 x^2\right )^2} \, dx &=\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{1}{217} \int \frac{255+100 x}{(1+2 x)^{5/2} \left (2+3 x+5 x^2\right )} \, dx\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{\int \frac{145-2050 x}{(1+2 x)^{3/2} \left (2+3 x+5 x^2\right )} \, dx}{1519}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{\int \frac{-8345-11700 x}{\sqrt{1+2 x} \left (2+3 x+5 x^2\right )} \, dx}{10633}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{2 \operatorname{Subst}\left (\int \frac{-4990-11700 x^2}{7-4 x^2+5 x^4} \, dx,x,\sqrt{1+2 x}\right )}{10633}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{\operatorname{Subst}\left (\int \frac{-998 \sqrt{10 \left (2+\sqrt{35}\right )}-\left (-4990+2340 \sqrt{35}\right ) x}{\sqrt{\frac{7}{5}}-\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{10633 \sqrt{14 \left (2+\sqrt{35}\right )}}+\frac{\operatorname{Subst}\left (\int \frac{-998 \sqrt{10 \left (2+\sqrt{35}\right )}+\left (-4990+2340 \sqrt{35}\right ) x}{\sqrt{\frac{7}{5}}+\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{10633 \sqrt{14 \left (2+\sqrt{35}\right )}}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{\left (5 \left (499-234 \sqrt{35}\right )\right ) \operatorname{Subst}\left (\int \frac{-\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}+2 x}{\sqrt{\frac{7}{5}}-\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{10633 \sqrt{14 \left (2+\sqrt{35}\right )}}-\frac{\left (5 \left (499-234 \sqrt{35}\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}+2 x}{\sqrt{\frac{7}{5}}+\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{10633 \sqrt{14 \left (2+\sqrt{35}\right )}}-\frac{\left (8190+499 \sqrt{35}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{\frac{7}{5}}-\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{74431}-\frac{\left (8190+499 \sqrt{35}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{\frac{7}{5}}+\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )} x+x^2} \, dx,x,\sqrt{1+2 x}\right )}{74431}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}-\frac{5 \sqrt{-\frac{6252271}{217}+\frac{376075 \sqrt{35}}{62}} \log \left (\sqrt{35}-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{1+2 x}+5 (1+2 x)\right )}{10633}+\frac{5 \sqrt{-\frac{6252271}{217}+\frac{376075 \sqrt{35}}{62}} \log \left (\sqrt{35}+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{1+2 x}+5 (1+2 x)\right )}{10633}+\frac{\left (2 \left (8190+499 \sqrt{35}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{2}{5} \left (2-\sqrt{35}\right )-x^2} \, dx,x,-\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}+2 \sqrt{1+2 x}\right )}{74431}+\frac{\left (2 \left (8190+499 \sqrt{35}\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\frac{2}{5} \left (2-\sqrt{35}\right )-x^2} \, dx,x,\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}+2 \sqrt{1+2 x}\right )}{74431}\\ &=-\frac{820}{4557 (1+2 x)^{3/2}}-\frac{4680}{10633 \sqrt{1+2 x}}+\frac{37+20 x}{217 (1+2 x)^{3/2} \left (2+3 x+5 x^2\right )}+\frac{5 \sqrt{\frac{2}{7 \left (-2+\sqrt{35}\right )}} \left (499+234 \sqrt{35}\right ) \tan ^{-1}\left (\sqrt{\frac{5}{2 \left (-2+\sqrt{35}\right )}} \left (\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}-2 \sqrt{1+2 x}\right )\right )}{10633}-\frac{5 \sqrt{\frac{2}{7 \left (-2+\sqrt{35}\right )}} \left (499+234 \sqrt{35}\right ) \tan ^{-1}\left (\sqrt{\frac{5}{2 \left (-2+\sqrt{35}\right )}} \left (\sqrt{\frac{2}{5} \left (2+\sqrt{35}\right )}+2 \sqrt{1+2 x}\right )\right )}{10633}-\frac{5 \sqrt{-\frac{6252271}{217}+\frac{376075 \sqrt{35}}{62}} \log \left (\sqrt{35}-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{1+2 x}+5 (1+2 x)\right )}{10633}+\frac{5 \sqrt{-\frac{6252271}{217}+\frac{376075 \sqrt{35}}{62}} \log \left (\sqrt{35}+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{1+2 x}+5 (1+2 x)\right )}{10633}\\ \end{align*}
Mathematica [C] time = 0.51755, size = 176, normalized size = 0.59 \[ \frac{1}{217} \left (\frac{20 x+37}{(2 x+1)^{3/2} \left (5 x^2+3 x+2\right )}-\frac{4680}{49 \sqrt{2 x+1}}-\frac{820}{21 (2 x+1)^{3/2}}+\frac{2 i \sqrt{5} \left (\sqrt{2-i \sqrt{31}} \left (9188 \sqrt{31}+15469 i\right ) \tanh ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{2-i \sqrt{31}}}\right )+\left (-9188 \sqrt{31}+15469 i\right ) \sqrt{2+i \sqrt{31}} \tanh ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{2+i \sqrt{31}}}\right )\right )}{10633}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.081, size = 660, normalized size = 2.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}{\left (2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.62435, size = 3170, normalized size = 10.71 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (2 x + 1\right )^{\frac{5}{2}} \left (5 x^{2} + 3 x + 2\right )^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}{\left (2 \, x + 1\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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